please answer each part to the question A 4.52 kg ball is thrown upward with an

Question

please answer each part to the question

A 4.52 kg ball is thrown upward with an initial speed of 19.63 m/s. Ignore air resistance when answering the following questions. What is the ball's initial kinetic energy? Submit Answer Tries 0/6 What is the ball's kinetic energy when it reaches its maximum height? Submit Answer Tries 0/6 What is the ball's gravitational potential energy (relative to Earth's surface) when it reaches its maximum height? Submit Answer Tries 0/6 What is the ball's maximum height? Submit Answer Tries 0/6 What is the ball's kinetic energy just before it returns to your hand? Submit Answer Tries 0/6

Explanation / Answer

m = mass of ball = 4.52 kg

v = speed of launch = 19.63 m/s

kinetic energy is given as

KE = (0.5) m v2 = (0.5) (4.52) (19.63)2 = 870.86 J

at maximum height , v = 0

so KE = (0.5) m v2 = (0.5) (4.52) (0)2 = 0 J

using conservation of energy

Gravitational potential energy at Top = kinetic energy at the bottom = 870.86 J

mgh =  870.86 J

(4.52) (9.8) h = 870.86

h = 19.7 m

m = mass of ball = 4.52 kg

v = speed of ball when it return = 19.63 m/s

kinetic energy is given as

KE = (0.5) m v2 = (0.5) (4.52) (19.63)2 = 870.86 J

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