3. A nonconducting spher charge of the object is Q>o a. Determine the e with cen

Question

3. A nonconducting spher charge of the object is Q>o a. Determine the e with center C and radius a has a spherically symmetric electric charge density. The total e magnitude and direction of the electric field at point P, which is a distance R > a to the right of and the sphere's center b. Determine the flux of the electric field through the spherical surface centered at C and passing through P 0 0 A point particle of charge -Q is now placed a distance R below point P. as shown above. c. Determine the magnitude and direction of the electric field at point P

Explanation / Answer

(A) from Gauss law,

E ( 4 pi R^2) = Qin / e0

E = Q / (4 pi e0 R^2) .....magnitude

direction -> to the right

(b) flux = Q / e0

(c) E1 = Q / (4 pi e0 R^2)

E2 = Q / (4 pi e0 R^2)

magnitude = sqrt(E1^2 + E2^2) = 0.354 Q / (pi e0 R^2)

direction = 45 deg below to the right

(d) (i) charge which are inside

ans: q2 and q3

(ii) all four charges

(iii) they are different.

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