1. A car weighing 15000N traveling 20m/s collides with a tree (in the image abov

Question

1. A car weighing 15000N traveling 20m/s collides with a tree (in the image above). The time of collision was 0.00035 seconds. What was the average force experienced in the collision? a. 10ONm b. 410Nm c. 30000Nm d. 60000Nm e. 600000Nm 2. What is the change in Kinetic Energy? a. 0J b. 300,000J c. 3,000,000J d. 15,000,000 e. 150,000,000J If, after the collision, the car was seen moving in the opposite direction at 20m/s, what would be the change in momentum? 3. a. ONm b. 210Nm c. 30000Nm d. 45000Nm e. 450000Nm 4. If the duration of the collision still took place in 0.00035 seconds, what is the average force experienced in the collision? a. 17*103N b. 43*106N c. 86 106N d. 17*107N e. 86*10'N

Explanation / Answer

1. impulse = change in momentum = F t

(15000/10 kg) (0 - 20) = F (0.00035)

F = 8.57 x 10^7 N

for N m., Ans: (8.57 x 10^7) (20 x 0.00035)
= 6000000
Ans(e)

2. Ki = (1500)(20^2 /2 ) = 300 000 J

Kf = 0

change = Ki - kf

Ans(b)

3. from (1), F = 86 x 10^6 N

Ans(c)

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