D University Physics Volu D Fisica para Cencias e l × \\ D Physics for Scientist

Question

D University Physics Volu D Fisica para Cencias e l × D Physics for Scientists a x-e Physics question Che X LON CAPA Friction x 0 (1) whatsApp C | loncapa.hep.uprm.edu/enc/72H3684898c7a2b024a9e3a0a57a4b23a94aac3b66667519fc5c0497f7df873d7c31f868a348cb4f58cc2d428962c5cf30752 Fisi3171-Agosto-2017 ERICK I PEREZ(Student section: 011) Main Menu Contents Grades Messages Courses Help Logout >, Timer Note., Evaluate 4-Feedback-Print Course Contents » » Cap5 Leyes de Newton » Friction Friction Points:1 M1 has a mass of 6.51 kg. It is on a horizontal surface, connected by a light string to a hook. Mass M2 can be increased smoothly by adding masses little at a time. The pulley has a negligible mass and no friction. Mi when M2 is 3.12 kg it begins to accelerate downwards at a rate of 1.85 m/s2. Calculate &Wk; for M1 on the surface. First calculate m knowing the force it takes to begin moving) and then k (from the given acceleration) and subtract. Tries 1/40 Previous Tries Post Discussio Send Feedback Activate Windows Go to Settings to activate Windows 1:14 PM O Type here to search 11/20/2017

Explanation / Answer

here,

M1 = 6.51 kg

M2 = 3.12 kg

let the coefficient of friction be u

accelration , a = net force /effective mass

1.85 = ( M2 * g - u * M1 * g) /(M1 + M2)

1.85 = ( 3.12 * 9.81 - u *6.51 * 9.81) /( 3.12 + 6.51)

solving for u

u = 0.2

the coefficient of friction is 0.2

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.