CAN YOU PLEASE SHOW THE STEPS THAT LEAD TO THE ANSWER? THE RIGHT ANSWER IS 103.5

Question

CAN YOU PLEASE SHOW THE STEPS THAT LEAD TO THE ANSWER? THE RIGHT ANSWER IS 103.50. THANKS IN ADVANCE.  

A block of mass M is pushed up a rough slope which makes an angle above the horizontal. The slope has coefficient of kinetic friction Hk. The block starts from rest, and subject to a force F which pushes up the slope with magnitude F If M-3.0kg, d-4.5m, F = 53.9N, =43.5°, and .-0.5, what is the final kinetic energy of the block? Answer in Joules Answer: 6196 The correct answer is: 103.50 Assignment 9

Explanation / Answer

let a be the accleration and f be the frictional force

so f = uk N

f = uk * mg cos theta

uk is Coeffiecint of Knetic friction

Net balancing force along the inclined plane is

F - mg sin theta -f = ma

a = (F - mg sin theta - uk mg cos theta)/m

F = 53.9 N

mg sin theta = 3 * 9.81 * sin 43.5 = 20.258 N

uk mg cos theta = 0.5* 3 * 9.81 cos 43.5 = 10.67 N

so

a = (53.9-20.258 -10.67)/3

a = 7.65 m/s^2

from kinematic eqaution

v^2 = 2a d

V^2 = 2 * a * 4.5

v^2 = 2* 7.65 *4.5

V^2 = 8.29 m/s

final Kinetic energy K = 0.5 mv^2

K = 0.5* 3 * 8.29^2

K = 103.275 Joules

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.