An electric kitchen range has a total wall area of 1.57 m2 and is insulated with

Question

An electric kitchen range has a total wall area of 1.57 m2 and is insulated with a layer of fiberglass 3.50 cm thick. The inside surface of the fiberglass has a temperature of 186°C, and its outside surface is at 33.5°C. The fiberglass has a thermal conductivity of 0.040 W/m · K. (a) What is the heat current through the insulation, assuming it may be treated as a flat slab with an area of 1.57 m2 = W
(b) What electric-power input to the heating element is required to maintain this temperature? = W An electric kitchen range has a total wall area of 1.57 m2 and is insulated with a layer of fiberglass 3.50 cm thick. The inside surface of the fiberglass has a temperature of 186°C, and its outside surface is at 33.5°C. The fiberglass has a thermal conductivity of 0.040 W/m · K. (a) What is the heat current through the insulation, assuming it may be treated as a flat slab with an area of 1.57 m2 = W
(b) What electric-power input to the heating element is required to maintain this temperature? = W An electric kitchen range has a total wall area of 1.57 m2 and is insulated with a layer of fiberglass 3.50 cm thick. The inside surface of the fiberglass has a temperature of 186°C, and its outside surface is at 33.5°C. The fiberglass has a thermal conductivity of 0.040 W/m · K. (a) What is the heat current through the insulation, assuming it may be treated as a flat slab with an area of 1.57 m2 = W
(b) What electric-power input to the heating element is required to maintain this temperature? = W

Explanation / Answer

A = 1.57 m^2

t = 3.5 cm

Ti = 186 C

To = 33.5 C

k = 0.04 W/m k

a. heat current, Q = kAdT/t = 0.04*1.57*(186-33.5)/3.5*10^-2

Q = 273.62 W

b. power input required = 273.62 W ( from conservation of energy)

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