Two frictionless carts are tied together with a piece of string and are at rest.

Question

Two frictionless carts are tied together with a piece of string and are at rest. Between them is a spring with k = 80 N/m, compressed a distance of 0.2 m. Each cart weighs 1 kg. If the spring is cut, allowing the carts to push apart, what is the final velocity of each?
Two frictionless carts are tied together with a piece of string and are at rest. Between them is a spring with k = 80 N/m, compressed a distance of 0.2 m. Each cart weighs 1 kg. If the spring is cut, allowing the carts to push apart, what is the final velocity of each?
Two frictionless carts are tied together with a piece of string and are at rest. Between them is a spring with k = 80 N/m, compressed a distance of 0.2 m. Each cart weighs 1 kg. If the spring is cut, allowing the carts to push apart, what is the final velocity of each?

Explanation / Answer

Compression in each cut portion of springs = 0.1 m. Each cut portion provides energy to corresponding cart.

0.5kx^2 = 0.5mv^2

v = sqrt(k/m) x

= sqrt(80/1) *0.1

= 0.8944 m/s answer

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