I need help with part D please. (11%:) Prohlem 1: Twc lenses are mc un ied d= 26

Question

I need help with part D please.

(11%:) Prohlem 1: Twc lenses are mc un ied d= 261: m Hparl on an uptical bench. The lical length (1.the list lens is fi 9.9 cm and that of the second lens is 5.9 cm. An object of height kn 4.3 cm is placed at distance of d 22 cm in front of the firstlens. 25%, Part (a) gnoring the second lens for now, at what distance, in centimeters, behind the first lens is the object's image Irmccl tiy thal lens? 25% Part (h) Calculate lhe magni litalin 1. I hal image, including its sign. 25%, Part (c) Which thoire besl desribes thal image? 25% Part d) Now consider the l wu lens system and the final irriage il larms, LE the image created by the second lens. What is he distance, in entimeters,belhe object ad its linal imagr? Grade Summary LD cotan asino acos) atan acotan sinhl) cosh tanh) cotanho 1. Degrees (J. Radians % per attempt) detalled view Subrnit Hints: 2% deduction per hint. Hints remainir :3 l'eedback 2% deductionr feedback

Explanation / Answer

here,

1)

for the first lens

object distance , do1 = 22 cm

focal length , f1 = 9.9 cm

let the image distance be di1

using the lens formula

1/f1 = 1/di1 + 1/do1

1/9.9 = 1/di1 + 1/22

solving for di1

di1 = 18 cm

for the seccond lens

object distance , do2 = 26 - 18 = 8 cm

focal length , f2 = 5.9 cm

let the image distance be di2

using the lens formula

1/f2 = 1/di2 + 1/do2

1/5.9 = 1/di1 + 1/8

solving for di2

di2 = 22.5 cm

the distance between the final image and the initial object , s = d + do1 + di2

s = 26 + 22.5 + 22 = 70.5 cm

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