Exercise 29.45 Part A At temperatures near absolute zero, Bc approaches 0.142 T

Question

Exercise 29.45 Part A At temperatures near absolute zero, Bc approaches 0.142 T for vanadium, a type-l superconductor. The normal phase of vanadium has a magnetic susceptibility close to zero Consider a long, thin vanadium cylinder with its axis parallel to an external magnetic field Bo in the +x-direction. At points far from the ends of the cylinder, by symmetry, all the magnetic vectors are parallel to the x-axis At temperatures near absolute zero, what is the magnitude of the resultant magnetic field B inside the cylinder for Bo = (0.130T) B= 0 T Submit My Answers Give Up Correct Part B What is the direction of the resultant magnetic field B inside the cylinder for this case? O in the +-direction in the--direction perpendicular to the x-axis the field is zero Submit My Answers Give Up Part C What is the magnitude of the resultant magnetic field B outside the cylinder (far from the ends) for this case? Submit My Answers Give Up

Explanation / Answer

Part B - As the field is zero inside the zylinder, there would be no direction. Therefore, correct option for part B is last option (The field is zero).

Part C - As the field inside the cylinder is zero, all of the applied field should be outside the cylinder. Therefore, Magnitude of magnetic field outside the cylinder is 0.130 T.

Part D - This field which is present outside the cylinder is in +ve x axis.

Part E - Magnetization M = - B0 / u0 where u0 is permeability and is equal to 4*pi*10-7.

Therefore, inside the cylinder M = - 0.130 / 4*pi*10-7 = -1.0345 * 105 A/m

Part H - As M is zero outside the cylinder, There would be no direction. The last option is correct one.

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