With the total energy equal to E = 0.5mv^2 + mgh = (0.5*274.4^2 + 9.81*11,887.2)

Question

With the total energy equal to E = 0.5mv^2 + mgh = (0.5*274.4^2 + 9.81*11,887.2) 333,400 = 51,430,654,740.8 J. Considering how one U.S. gallon has an energy content of 33.70, which can also be converted to 121,320 x 10^3 J. Estimate how much gasoline superman should have carried with him in order to achieve his feat of landing a malfunctioning airplane gently onto a football field. Now reflect and write if it is reasonable to assume that superman owes his energy in gasoline like chemical substances.

Explanation / Answer

E = 0.5mv^2 + mgh = (0.5*274.4^2 + 9.81*11,887.2) 333,400 = 51,430,654,740.8 J
1 US gallon = 33.70 = 121,320 x 10^3 J.

KE of the plane = 0.5mv^2 + mgh
v = Mach 0.8 = 0.8*343 = 274.4 m/s ( sapmpe speed)
m = 400,000 kg ( sampe mass)
h = 10,000 m ( sampe altitude)

hence E = 5429907200 J
number of US galons = 5429907200/121320*10^3 = 44.7569 gallons
hence superman cannot use oil as source of energy as too much oil is required to be carried for this purpose

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