Exercise 29.6 Part A A coil 3.80 cm radius, containing 580 turns, is placed in a

Question

Exercise 29.6 Part A A coil 3.80 cm radius, containing 580 turns, is placed in a uniform magnetic field that varies with time according to B ( 1.20×10-2 T/s )t + ( 3.15x10-5 T/s4 )t4. The coil is connected to a 540- resistor, and its plane is perpendicular to the magnetic field. You can ignore the resistance of the coil Find the magnitude of the induced emf in the coil as a function of time. = 1.01x10-2V +( 1.06× 10-4 v) = 3.16x10-2 V +( 8.29x10-5 V/s*)e =3.16x10-2 V +(3.32×10-4 V/s*)t3 = 1.01 x 10-2 V + ( 3.32x10-4 V/s*)t3 . Submit My Answers Give Up Correct Part B What is the current in the resistor at time to 4.95 s? Submit My Answers Give Up

Explanation / Answer

Current is given by:

i = V/R (from Ohm's law)

R = 540 ohm

V = EMF = 3.16*10^-2 V + (3.32*10^-4)t^3

At t = 4.95 sec

EMF = 3.16*10^-2 + (3.32*10^-4)*(4.95)^3 = 0.0719 V

So,

i = 0.0719/540 = 1.33*10^-4 Amp.

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