You are given three resistors: two 4? resistors and one 6? resistor. What is the

Question

You are given three resistors: two 4? resistors and one 6? resistor. What is the value in Ohms ( ? ) of the smallest-valued resistor that can be fabricated by combining these three resistors?
Given that each individual resistor can dissipate up to 1 watt of power before burning up, how much total power in watts ( W ) can the smallest-valued composite resistor dissipate before burning up?

I found out the value in Ohms for of the smallest value resistance. Which is 1.5 ohms,
i did it by arranging the resistors in parallel. However I got stuck when finding the total
power dissipated. Please explain step by step the solution to this problem.

Explanation / Answer

The smallest valued resistor will be obtained by taking each of them in parallel.

This amounts to 1.5 ohm. That part of your is correct

The voltage across the combination will be same.

Let it be 2 V

So the power dissipation is given as

2^2/4 + 2^2/4 + 2^2/6

=1+1+0.66 = 2.66 W

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