The acceleration of a particle is defined by relation a=-10v,where \"a\" is expr

Question

The acceleration of a particle is defined by relation a=-10v,where "a" is expressed in m/s^2 and "v" in m/s. When t=0, thedisplacement is x=0m, and the velocity is v= 30m/s. Find thedistance that the particle will travle in a stratight line beforecoming to rest. Help setting this up would be great. The acceleration of a particle is defined by relation a=-10v,where "a" is expressed in m/s^2 and "v" in m/s. When t=0, thedisplacement is x=0m, and the velocity is v= 30m/s. Find thedistance that the particle will travle in a stratight line beforecoming to rest. Help setting this up would be great.

Explanation / Answer

At t = 0, x = 0 the particle is put in motion at initial velocity = v = 30 m/s For the particle to come to rest ()a negative accelerationmust be applied which is given to be a = -10 v final velocity vf = 0 Distance travelled is required = x Use the kinematics equation v f2 - v 2 = 2ax - v 2 = 2x(-10v) solving for x x = v / 20 x = 30/20 x = 1.5 m - v 2 = 2x(-10v) solving for x x = v / 20 x = 30/20 x = 1.5 m

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