Question 2: A rigid tank contains 10 kg of water vapor at 1.0 bar and a specific

Question

Question 2:
A rigid tank contains 10 kg of water vapor at 1.0 bar and a specific volume of 2.36 m3/kg.

(a) Calculate the temperature (in °C) using the Ideal Gas Law if Ru = 8.314 kJ/kmol•K and the molecular weight of H20 = 18 kg/kmol.

(b) Find the temperature of the water vapor using the property tables [see attached].

(c) Calculate the % error
[ = (accurate_value) - (comparison) accurate_value x 100 ] associated with using the ideal gas law to model this gas. To receive complete credit you must complete the calculation and explain which value (a) or (b) is more accurate.

Explanation / Answer

(a) by using ideal gas law
PV=mRT
Pv=RT
1*100*2.36=(8.314/18)*T
T(a)=510.945K=237.945C (b) by using superheated water tables at P=1.0bar and v=2.36m^3/kg by using interpolation T=200+(250-200)(2.36-2.17226)/(2.40604-2.17226) T(b)=240.153C (c) percent error {T(b)-T(a)}/T(b)*100 % error=(240.153-237.945)/240.153*100 % error=0.9194%

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