A rectangular, horizontal flow sedimentation basin is to be designed to remove p

Question

A rectangular, horizontal flow sedimentation basin is to be designed to remove particles with a settling velocity greater than 0.071 feet per minute. The design flow through the basin is 20 million gallons per day. The maximum flow through velocity in the tank in 1.5 feet per minute. The minimum tank depth is 10 feet What are the three tank dimensions for this tank, length, width and water depth. (There are many possible solutions to this problem so show work) Do not deduct for inlet or outlet zones.

Explanation / Answer

Settling velocity = 0.071 ft/min 0.071 (ft / min) = 0.00036068 m / s Q = 20 000 000 US gallons/day = 75 708.2357 meters^3/day = 0.8762527 m^3/s max flow velocity = 1.5 ft/min = 0.00762 m / s so surface area = Q/velocity = 115 m^2 so length x breadth = 115 and length/retetion time = settling velocity =0.00036068 m / s so retention time = V/Q length x Q/V = 0.00036068 m / s V = 115 x depth length/depth = 0.047335 aand we have length x breadth = 115 m^2 so from this one possible combination is breadth = 10 m length = 11.5 m depth = 242.95 m .

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