A 1060-kN load P is applied to the granite block shown. Determine the resulting

Question

A 1060-kN load P is applied to the granite block shown. Determine the resulting maximum value of (a) the normal stress, (b) the shearing stress. specify the orientation of that plane on each of these maximum values occurs. Step 1 of 4 Granite block under applied load is as shown Step 2 of 4 Calculate the area of the granite block, A0 = 140 times 140 = 19600 mm2 Calculate the normal stress using the relation, sigma = P/A0 cos2 theta Substitute 19600 mm2 for A0 and 1060 kN for P. sigma = 1060 times 103/19600cos2 theta = 54. 08cos2 theta Step 3 of 4 Maximum tensile stress at theta = 90 degree sigma = 54. 08 cos2 theta sigma = 0 Maximum compressive stress occurs at theta = 0 degree sigma =54. 08cos2 theta sigma = 54. 08 MPa Therefore the maximum tensile stress is theta = 0 degree The maximum compressive stress is 54. 08 MPa Step 4 of 4 Calculate the shear stress using the relation, tau = P/2A0 Where P is the applied load, 19600 mm2 for A0 tau = 1060 times 103/2 times 19600 = 27 MPa Maximum shear stress occurs at an angle theta = 45 degree Therefore the maximum shear stress is 27 MPa

Explanation / Answer

www.me.mtu.edu/~mavable/Book/Chap3.pdf

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