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A 1060-kN load P is applied to the granite block shown. Determine the resulting

ID: 1847790 • Letter: A

Question

A 1060-kN load P is applied to the granite block shown. Determine the resulting maximum value of (a) the normal stress, (b) the shearing stress. Specify the orientation of that plane on which each of these maximum values occurs. A centric load P is applied to the granite block shown. Knowing that the resulting maximum value of the shearing stress in the block is 18 MPa, determine (a) the magnitude of P, (b) the orientation of the surface on which the maximum shearing stress occurs, (c) the normal stress exerted on that surface, (d) the maximum value of the normal stress in the block. Link BC is 6 mm thick, has a width w = 25 mm, and is made of a steel with a 480-MPa ultimate strength in tension. What is the safety factor used if the structure shown was designed to support a 16-kN load P? Link BC is 6 mm thick and is made of a steel with a 450-MPa ultimate strength in tension. What should be its width w if the structure shown is being designed to support a 20-kN load P with factor of safety of 3? A 3 / 4-in.-diameter rod made of the same material as rods AC and in AD in the truss shown was tested to failure and an ultimate load of 29 kips was recorded. Using a factor of safety of 3.0, determine

Explanation / Answer

1.35 ) a) normal stress will be maximum on the plane perpendicular to the direction of load here p = 1060 kN area of cross section of block = 0.140*0.140 m2 max normal stress = p/area = 1060/( 0.140*0.140 ) =54081.63 k Pa b) shear stress maximum on the plane inclined 45 degree with central axis value is = max normal stress * sin 45 = 38241.49 kPa

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