owLv2] Online teaching Studies of existing cells to the mi number of genes for a

Question

owLv2] Online teaching Studies of existing cells to the mi number of genes for a living cell have suggested that 206 genes are sufficient. If the ratio of protein-c genes is the same in this minimal organism as the genes of Escherichia coli (0.980), how many proteins are represented in these 206 genes? The Escherichia coli genome contains 4377 genes and 5175720 base pairs How many base pairs would be required to form the genome of this minimal organism if the genes are the same size as Escherichia coli genes? 10 iteen attempts rernaining

Explanation / Answer

Genes of minimal organism = 206

Ratio of protein coding genes for E.Coli is same as for minimal organism = 0.98= x= no. of proteins/no. of genes

206*0.98 = 201.88

No of genes in E.coli 4377; No. of Base Pairs 5175720

Ratio of 4377/5175720 =0.00084

No of genes/x= 0.00084

206/0.00084=x = 245238 (no. of base pairs)

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