When evaluating the current at a given time, in a sinusoidalfunction, do you hav

Question

When evaluating the current at a given time, in a sinusoidalfunction, do you have to convert the angles to like angles or justpunch them in as is? such as i(t) 2Cos(400t + 23.13) if evaluating at .1 sec orsomething like that, do you have to convert either 400t to degreesor 23.13 to radians, or just punch this into the calculatorwith as is with the t value. thank you in advance. When evaluating the current at a given time, in a sinusoidalfunction, do you have to convert the angles to like angles or justpunch them in as is? such as i(t) 2Cos(400t + 23.13) if evaluating at .1 sec orsomething like that, do you have to convert either 400t to degreesor 23.13 to radians, or just punch this into the calculatorwith as is with the t value. thank you in advance.

Explanation / Answer

But it is not necessary to keep everything inradians. In your given example, if it is given that 400 is indegrees/Sec and 23.13 is in degrees. Then you dont need to convertanything. Just punch in the time value of t=0.1 and make sure yourcalculator is working in degree mode. Else if one of these 2 figures is in radians and the other isin degree, then convert any 1 of them and make them of the sameunit. Just see that 400t and 23.13 are in the same units and yourcalculator is in the same mode. Work with radians if there are approximations to be made.Otherwise , if the figures are given in degrees, I would go aheadwith that.. Just make sure that all the figures are in the same unit.
I hope you got your answer.

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