An electron is placed at the origin. What is the direction of the electric field

Question

An electron is placed at the origin. What is the direction of the electric field, created by this electron, at points on the +y axis? +y -y +x -X more info is needed to determine Three hollow, conducting spheres are concentric (have the same center point) as shown in the cross section. The inner sphere has a net charge of + 1C, the middle sphere has a net charge of +2C, and the outer sphere has a net charge of +3C. The inner and outer radii of the spheres are at distances 0.1, 0.2, 0.3, 0.4, 0.5, 0.6 meters from the center. There are no other charges in the system and all charges remain at rest. What is the surface charge density on the outer surface of the largest sphere? 3.33 C/m^2 2.83 C/m^2 2.33 C/m^2 1.83 C/m^2 1.33 C/m^2

Explanation / Answer

here ,

3.

as the electron is negatively charged ,

the direction of electric field will be towards the electron

hence , at the y axis , the direction of electric field is b) -y axis

4.

for the inner sphere ,

charge on the outer shell , q1 = 1 C

for the middle shell

charge on the inner surface = - q1 = -1 C

charge on the outer surafce = 2 - (1) = 3 C

for the large shell

charge on the inner shell = -3 C

charge on the outer shell = 3 - (-3)

charge on the outer shell = 6 C

Now,

surface charge density = charge on the outer surface/(area)

surface charge density = 6/(4pi * 0.6^2)

surface charge density = 1.33 C/m^2

the surface charge density is e) 1.33 C/m^2

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