In the following diode bridge full-wave rectifier, ac voltage Vin is 50 Vrms, 60

Question

In the following diode bridge full-wave rectifier, ac voltage Vin is 50 Vrms, 60Hz.

1. Determine the Vin peak value V_in,p

2 Derive expressions for Diode PIV and load peak voltage V_RLp in terms of V_in,p

3. When Vin is at positive peak, calculate

    a. The peak value of V_RL,p

     b. PIV on diodes

In the following diode bridge full-wave rectifier, ac voltage Vin is 50 Vrms, 60Hz. Determine the Vin peak value V_in,p Derive expressions for Diode PIV and load peak voltage V_RLp in terms of V_in,p When Vin is at positive peak, calculate The peak value of V_RL,p PIV on diodes

Explanation / Answer

1) Vin p   = 50*sqrt(2) =70.7 v

2) piV = Vinp =70.7 v

    V_RLp = 70.7 *sin(2*pi*60*t)

3) a ) peak V_RLp = Vin = 70.7 v

      b ) PIV on diodes =0

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.