g=9.81 and pwater(water density)= 1000kg/m^3 1)Assuming there are both a pressur
ID: 1860889 • Letter: G
Question
g=9.81 and pwater(water density)= 1000kg/m^3
1)Assuming there are both a pressure gage and a manometer attached to a gas tank which has a pressure lower than Patm. If the reading on the pressure gage is 10kPa and atmospheric pressure is 100kPa, determine (a) the absolute pressure of the tank, and (b) the height of the fluid between the two fluid levels in the manometer, given the fluid is has a specific gravity of 1.5.
2)Please calculate (a) the energy of a 1150-kg car consumes if it is driving at a velocity of 20m/s and a 100 m-long uphill road with a slope of 10
Explanation / Answer
1a) absolute pressure = atm pressure + gage pressure = 110 kPa
1b) density of manometer fluid = 1.5* water density = 1500 kg/m^3
hence, height difference = (pressure in tank = atmospheric pressure) / (fluid density * g)
= (110-100)*10^3 / (1500*9.81)
= 0.67 m
2a) since friction and other losses are negligible, and the car is driven at a constant velocity, enegry consumed is equal to the potential energy gained = m*g*h = 1150*9.81*100*sin(10) = 195.9 kJ
2b) difference in kinetic energy = 1/2*m*(v2^2 - v1^2) = 1/2 * 1150*(100-4) = 55.2 kJ
power required = energy requried / time = 55.2 kJ/0.5s = 110.4 kW
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