g=10 m/s speed of sound= 350 m/s #2 Vibrating String The pipe goes down a hill o
ID: 2017218 • Letter: G
Question
g=10 m/s
speed of sound= 350 m/s
#2 Vibrating String
The pipe goes down a hill of height 40 meters and comes out. The pipe at this point is a sequence of 2 centimeters to a side While the pump is running, what is the pressure; and velocity of the water as it comes out? What in the pressure and velocity of the fluid coming out if all variables remain the same except that the fluid is now liquid mercury' The units for your answer must be in atm or metres per second. A pulley is 1.8 meters away from the wall. A 4 meter string that has a mass of 25 grams has one end attached to the wall and the other end hung over the pulley. A iron mass is hung from the end of the string hanging oil the pulky. When plucked, it produces a fundamental frequency of 2000 Hz. What is the mass of their iron? Take this mass and experiment to the moon and find its 1st overtone and 3rd harmonic. The answers must use the units kg or Hz. You are on a train moving at velocity v toward station. The velocity of sound in air is x. The station blows a whistle at some frequency, f. As you approach, you bear it at frequency g as you approach and at frequency h as leave. What is the equation to determine the velocity v of the train? YouExplanation / Answer
Given: Frequency of the string f= 1/2L sqrt(T/) ........ (1) 4L2f2 = T/ T = 4L2f2 * = 4L2f2(m/L) = 4*(4)2(2000 Hz)2(25*10-3/4) = 16*105 N T = m g m = T/g = 1.6*105 kg (ii) T = m g = (1.6*105 kg )*(9.8 /6) = 2.6*105 N f = v/2L v = f*2L = 2000 Hz * 2 *4 = 16*103 m/sec (i) first overtone = second Harmonic so n = 2 fundamental frequency f = nv/2L = 32*103 m/sec/2*4 m = 4000 Hz for third harmonic n = 3 f = nv/2L = 48*103 m/sec/2*4 m = 6000 Hz T = m g m = T/g = 1.6*105 kg (ii) T = m g = (1.6*105 kg )*(9.8 /6) = 2.6*105 N f = v/2L v = f*2L = 2000 Hz * 2 *4 = 16*103 m/sec (i) first overtone = second Harmonic so n = 2 fundamental frequency f = nv/2L = 32*103 m/sec/2*4 m = 4000 Hz for third harmonic n = 3 f = nv/2L = 48*103 m/sec/2*4 m = 6000 Hz = 48*103 m/sec/2*4 m = 6000 HzRelated Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.