15.1 Assuing that only CaCO3 is produced, calculate the daily production rate (i

Question

15.1

Assuing that only CaCO3 is produced, calculate the daily production rate (in tons/day) of a 55%-solids sludge fro a 90%-efficcient limestone FGD system on a 600-MW power plant burning a 3.5%-sulfur coal. The plant has a thermal efficiency of 35%, and the coal has a heating value of 12,000 BTU/lb. Assume that the limestone is 95% CaCO3 and 5% inert substances, and that the ratio of the actual amount of limestone fed to the theoretical amount required is 1.15. Attempt at Solution:

The correct answer from the back of the book is 1476tons/day 5 stars for steps leading to correct solution

Explanation / Answer

Your answer is correct upto the stochiometry alkalinity step..Follow these steps....these will help

After finding stochimetry alkalinity

- Convert Sulfur removed from lbs/hr to moles/hr = (sulfur removed x mole/MW sulfur lbs) 32.065 MW

-get theoretical Ca lbs/hr = moles Sulfur/hr x (1 S/ 1 Ca) x MW Ca.

-Get theoretical limestone feed = theoretical Ca x (MW CaCO3/ MW Ca)

-Add up all the sludge components (everything is in lbs/hr)

CaSO3 lb/hr = theoritical S moles/hr x (1 CaSO3/1 S) x (MW lbs CaSO3/mole CaSO3)

-Unreacted Limestone = theoretical limestone x0.15

-Inert substances in limestone = theoretical limestone x 1.15 x 0.05

-Water = (CaSO3 + unreacted limestone + inert) x (1-0.55)

Add it up, convert lbs/hr to tons/day.

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