Compute the amount of work involved in transferring a charge of two Coulombs a)

Question

Compute the amount of work involved in transferring a charge of two Coulombs

a) from the negative to the positive electrode;

b) from the negative electrode to the positive electrode along a 45 degree angle;

c) from the negative electrode to the positive electrode and then back to the first one;

d) along an equipotential line

Change in position Voltage/potential difference 6cm (closest to negative electrode) -8.61 5cm -7.24 4cm -5.97 3cm -4.67 2cm -1.75 1cm (closest to the positive electrode) -0.85

Explanation / Answer

Work done in moving a charge q in varying potential,
W = q ( Vf - Vi)
where Vf is potential at final position, Vi is potential at initial position

a) W = 2( -0.85 - (-8.61) )
        = 15.52 J

b) work done, depends only on the final and initial potential, not on the path followed
so W = 15.52 J

c) As charge comes back to initial potential, work done = 0

d) Along equipotential line means, charge is moving along the line, along which potetial remain same, hence W=0

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