In the circuit at right, the battery has a voltage of 6.0 V, and each of the two
ID: 1872407 • Letter: I
Question
In the circuit at right, the battery has a voltage of 6.0 V, and each of the two resistors labeled R has a resistance 20ohm. What is the current in the circuit and the potential difference across the 10ohm resistor when the switch is open? When the switch is closed? In the circuit at right, the battery has a voltage of 6.0 V, and each of the two resistors labeled R has a resistance 20ohm. What is the current in the circuit and the potential difference across the 10ohm resistor when the switch is open? When the switch is closed? In the circuit at right, the battery has a voltage of 6.0 V, and each of the two resistors labeled R has a resistance 20ohm. What is the current in the circuit and the potential difference across the 10ohm resistor when the switch is open? When the switch is closed? Switch 10Explanation / Answer
a)
when the switch is open ,equivalent resistance
Req =10+20=30 ohms
Total current flowi=0.2ng is
I=E/Req =6/30 =0.2A
Current through 10 ohms resistor is
I10=0.2 A
potential difference across 10 ohms is
V10=0.2*10=2V
b)
when switch is closed ,the equivalent resistance
Req =10+(1/20 +1/20)-1=20 ohms
Total current
I=6/20=0.3A
Current through 10 ohms resistor is
I10=0.3A
Voltage across 10 ohms is
V10=0.3*10=3 Volts
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