Chapter 21, Problem 14 GO A charged particle with a charge-to-mass ratio of lql/
ID: 1874426 • Letter: C
Question
Chapter 21, Problem 14 GO A charged particle with a charge-to-mass ratio of lql/m = 5.7 × 108 C/kg travels on a circular path that is perpendicular to a magnetic field whose magnitude is 0.65 T. How much time does it take for the particle to complete one revolution? the tolerance is +/-696 GO TUTORIAL LINK TO TEXT By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSWER Earn Maximum Points available only if you answer this question correctly in four attempts or lessExplanation / Answer
in magnetic field,
q v B = m v^2 / r
r = m v / q B
T = 2 pi r / v = 2 pi m / q B
T = (2 pi / B) / (q / m)
T = (2 pi / 0.65) / (5.7 x 10^8)
T = 1.70 x 10^-8 sec
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