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Chapter 21, Problem 14 GO A charged particle with a charge-to-mass ratio of lql/

ID: 1874426 • Letter: C

Question

Chapter 21, Problem 14 GO A charged particle with a charge-to-mass ratio of lql/m = 5.7 × 108 C/kg travels on a circular path that is perpendicular to a magnetic field whose magnitude is 0.65 T. How much time does it take for the particle to complete one revolution? the tolerance is +/-696 GO TUTORIAL LINK TO TEXT By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSWER Earn Maximum Points available only if you answer this question correctly in four attempts or less

Explanation / Answer

in magnetic field,

q v B = m v^2 / r

r = m v / q B


T = 2 pi r / v = 2 pi m / q B

T = (2 pi / B) / (q / m)

T = (2 pi / 0.65) / (5.7 x 10^8)

T = 1.70 x 10^-8 sec

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