(25%) Problem 5: A positively charged particle Q1-25 nC is locked into place at
ID: 1874495 • Letter: #
Question
(25%) Problem 5: A positively charged particle Q1-25 nC is locked into place at the origin. A negatively charged particle Q,--36 nC of mass m = 7.5 g is located a distance d= 15 cm along the positive x-axis from the positively charged particle. Q, Otheexpert 33% Part (a) What is the magnitude of the electric force, F in newtons, that acts on the charge Q2? a 33% Part (b) What is the direction of the force on charge 33% Part (c) What is the magnitude of the acceleration, a in ms", experienced by charge Q?Explanation / Answer
5. (A) F = k Q1 Q2 / d^2
F = (9 x 10^9)(25 x 10^-9)(36 x 10^-9) / 0.15^2
F = 3.6 x 10^-4 N....Ans
(B) charges are of opposite sign hence they will attract.
to the left (Or towards Q1)
(C) a = F / m
a = (3.6 x 10^-4) / (7.5 x 10^-9)
a = 48000 m/s^2
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