A pair of parallel plates can be used to store charge. The property of the plate

Question

A pair of parallel plates can be used to store charge. The property of the plates which is related to their capacity to hold charge is called the capacitance. This quantity is determined by the geometrical properties of the parallel plates as discussed in the text.
If you have a pair of plates, each with an area of 6.30×10-3 m2 that are separated by a distance of 7.20×10-4 m. Assume that there is no dielectric material separating the plates (=1.0). What is the capacitance?

The magnitude of the charge stored on one of the plates depends on the capacitance and the voltage placed across the plates. Suppose the you place a voltage (electric potential) of 5.30 V across a 6.80 F capacitor. What is the charge stored by the capacitor?

You pull a capacitor out of the drawer, hook it up to 7.50 V voltage source and find that it stores a charge of 15.8 µC. What is the capacitance of the capacitor?

Explanation / Answer

Capacitance = kAeo / d

= 1*6.3*10^-3*8.85*10^-12 / 7.2*10^-4

= 7.74*10^-11 F = 77.4 pF

charge stored = CV = 6.8*5.3 = 36.04 uC

capacitncae = Q/V = 15.8 / 7.5 = 2.1 uF

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.