Consider a parallel plate capacitor having a potential difference across its ele

Question

Consider a parallel plate capacitor having a potential difference across its electrodes of 1020 V. The plates are separated by a distance of 10 mm. If a proton and an electron, each having a magnitude of charge e = 1.602x10-19 C, are released from rest at a point located exactly in between the two electrodes, which charged particle, if either, will strike an electrode first?

electron, proton, or both the same

The work done by the electric force to move a charge from Point A to Point B is 161 J. If you determine the charge to be +0.235 C. What is the potential difference VA-VB?

Explanation / Answer

field inbetween the plates is E (that is constant)

electric force, fe = q E

a = Fe / m = q E / m

me < mp

so election have greater acceleertion hence it will strike first,

Ans: Electron.

--------------------------------

W = - q deltaV

161 = - 0.235 (VB - VA)

VA - VB =685 Volt ....Ans

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