Cheetahs can accelerate to a speed of 20.0 m/s in 2.50 s and can continue to acc

Question

Cheetahs can accelerate to a speed of 20.0 m/s in 2.50 s and can continue to accelerate to reach a top speed of 29.0 m/s. Assume the acceleration is constant until the top speed is reached and is zero thereafter. (a) Express the cheetah’s top speed in mi/h. (b) Starting from a crouched position, how long does it take a cheetah to reach its top speed, and how far does it travel in that time? (c) If a cheetah sees a rabbit 120 m away, how long will it take to reach the rabbit, assuming the rabbit does not move?

Explanation / Answer

1)1 m/s = 2.23694 mile/hr

So ..

29m/s = 64.8712 miles/hr Answer

2)a = 20/2.5 = 8m/s^2

v = u+at

==> t = v-u /a = 29-0/8 = 3.625 second

v^2 = u^2 +2as

==> s = v^2-u^2/2a = 29^2-0^2 /16 = 52.5625 m Answer

3) for 8 s chettah accelerates

distance covered in that time is 52.5625

distance left to cover = 120-52.5625 = 67.44 m

after that it moves with constant velocity so

t = s/v = 2.325 s

total time =3.625 s + 2.325 s

=5.95 s Answer

I hope help you ....

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