ET6-QRT1: Two CHARGED OBJECTS-WORK AND ENERGY Shown below are the positions of t
ID: 1877764 • Letter: E
Question
ET6-QRT1: Two CHARGED OBJECTS-WORK AND ENERGY Shown below are the positions of two small objects with identical masses and different charges. The smaller charge is fixed in place while the +4g charge with mass m is free to move. At time t,, the charges are at rest and separated by a distance d. At a later time ty, the charges are separated by a distance 2d Time f Time t, +4q, m , m 4q, m 2d A. Is the work done by the +q charge on the +4q charge during the time interval from t, to t, positive, negative, or zero? If the work done cannot be determined with the given information, state that explicitly. Explain. so peshve will the electric potential energy of the system of two charges increase, decrease, or remain the same during the time interval from t, to t,? If the change in electric potential energy cannot be determined with the given information, state that explicitly. Explain. B. C. Will the kinetic energy of the system of the two charges increase, decrease, or remain the same during the time interval from t, to t,? If the change in kinetic energy cannot be determined with the given information, state that explicitly. Explain. D. If the +4q charged object with mass m is replaced with a +dg charged object with a mass of 2m, will the quantities in parts A, B, and C be larger, smaller or the same as determined in parts A, B, and C? Explain. If the +4q charged object with mass m is replaced with a +124 charged object with the same mass m, will the quantities in parts A, B, and C be larger, smaller, or the same as determined in parts A, B, and C? Explain E.Explanation / Answer
A] positive because displacement is in direction of force.
B] Electric potential energy decreases: U = kq1q2/r here separation r is increases, so U decreases.
C] Kinetic energy increases. It is by energy conservation, since U decreases, KE must increase.
D] Since force depends on charge, not mass here,
Work done will be same.
change in potential energy will also be same.
change in Kinetic energy will also be same.
E] Since force depends on charge here,
Work done will be more.
decreases in potential energy will also be more.
increase in Kinetic energy will also be more.
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