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D https://usg 1Sil.theexpertta.com/Common/TakeTutorialAssignment.aspx perimti cTableworks.p...-Bio DAT breakdown (don) 110% 1 a Search Class Management Help Chapter 20 Begin Date: 9/2/2018 1:00:00 AM- Due Date: 9/10/2018 11:55:00 PM End Date: 9/11/2018 11:55:00 PM (990) Problem 10: A capacitor has a potential difference of Vo 295 V between the plates. When the switch S is closed, it is discharged through a resistor of R-7.5 k2. At time t = 10 seconds after the switch is closed, the potential difference between the capacitor plates equals Vc 1.0 V Randomized Variables Vo 295 V R=7.5kS2 Othee 33% Part (a) Calculate the capacitance of the capacitor in farads ted ted eted eted tan() | | ( sinO cotan) asin acos) atanO acotanO sinhO coshO cosO leted tanhO cotanhO ew

Explanation / Answer

part A)

let the capacitance is C

Now, for discharging of capacitor

Vc = Vo * e^(-t/(R * C)))

1 = 295 * e^(-10/(7.5 *10^3 * C ))

solving for C

C = 0.0002344 F

the capacitance is 0.0002344 F

part B)

maximum current = 295/(7.5 *10^3) A

maximum current = 0.0393 A

part C)

T = R * C = 7.5 *10^3 * 0.0002344

T = 1.76 s

Now, for the current

I = Io * e^(-t/T)

I = 0.0393 * e^(-t/1.76)

the current I is 0.0393 * e^(-t/1.76) A

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