If a plant cell with a solute potential of -0.2 MPa is placed in a beaker of pur

Question

If a plant cell with a solute potential of -0.2 MPa is placed in a beaker of pure water, at equilibrium it will have a pressure potential of +0.2 MPa because the cell wall prevents cell expansion. If that cell is then placed in a solution with a solute potential of -0.3 MPa that is open to the atmosphere (draw a picture if it helps you),

a.) Water will flow out of the cell

b.) Water will flow into the cell

c.) There will be no net movement of water

d.) Solutes will move out of the cell

e.) The cell will explode

a.) Water will flow out of the cell

b.) Water will flow into the cell

c.) There will be no net movement of water

d.) Solutes will move out of the cell

e.) The cell will explode

Explanation / Answer

The correct option is the water will flow into the cell as the outside the solute concentration is less hence it is a hyperosmosis condition.. It will not burst as it can maintainmthat wall pressure

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