(996) Problem 10: In a particular Cartesian coordinate systern, they and z-compo
ID: 1880417 • Letter: #
Question
(996) Problem 10: In a particular Cartesian coordinate systern, they and z-components of the acceleration are zero and the x. component varies as given by the following function: ax()--45S+45t, where t is in seconds and a is in meters per square second. The particle's velocity at 0 was pointed towards the positive x-axis and has a magnitude of 15 m/s. G> 11% Part (a) Find the instantaneous acceleration, in meters per square second, at t-1 sec. Grade Summary Potential Submissions ax 096 100% cos0 cotan asin sin0 tan() Attempta remaining:1'2 (5% per attempt) detailed view atan acotan sinh0 cosh0 tanhcotanh0 END Degrees Radians Submit Hint I give up Hints: 100 deduction per hint. Hints r Feedback: 2% deduction per feedback Submission History Date Time Answer Hints Feedbackk il % Part (b) Find the instantaneous acceleration, in meters per square second, at t 2 sec. 11% Part (c) Find the instantaneous acceleration. in meters per square second, at-3 sec 11% Part (d) Find the instantaneous velocity, in meters per second, at t= 1 sec. 11% Part (e) Find the instantaneous velocity, in meters per second, at t = 2 sec. ll% Part (f) Find the instantaneous velocity, in meters per second, at t-3 sec. 11% Part (g) If the particle was at x-0 at t-0. ?nd the position in meters of the particle at t-1 s. 4) 11 % Part (h) Ifthe particle was at x-0 at t = 0, 2nd the position in meters of the particle at t = 2 s. 1190 Part (i) If the particle was at x-0 at t-0. ?nd the position in meters of the particle at t-3 s. 11:31 AM 99+ 9/18/2018 7Explanation / Answer
Given,
ax(t) = -45 + 45t m/s2 , ay(t) = 0 , az(t) = 0
initial velocity, ux = 15 m/s , uy = 0 , uz = 0
(a) instantaneous acceleration, at , t = 1s , ax = -45 + 45x1 = 0 m/s2
(b) instantaneous acceleration, at , t = 2s , ax = -45 + 45x2 = 45 m/s2
(c) instantaneous acceleration, at , t = 3s , ax = -45 + 45x3 = 90 m/s2
(d) instantaneous velocity is given by, vx(t) = ux + Integration (-45 + 45t) dt = 15 - 45t + 22.5t2 m/s
for t = 1s , velocity = 15 - 45x1 + 22.5x1 = -7.5 m/s
(e) for t =2s , velocity = 15 - 45x2 + 22.5x4 = 15 m/s
(f) for t = 3s , velocity = 15 - 45x3 + 22.5x9 = 82.5 m/s
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