(996) Problem 3: A man stands in front of a vertical plane mirror, as shown in t
ID: 2304456 • Letter: #
Question
(996) Problem 3: A man stands in front of a vertical plane mirror, as shown in the figure. His eyes are 1.5 m above the floor and the top of his head is 0.15 m higher than that. Othcexpertta.com eight abo ottom edge gure. Grade Summary Deductions Potential 0% 100% sin0 cosO cotan0asin acos0 atan0 acotan sinhO cosh0 tanh cotanh0 O Degrees Radians tan Submissions ts remaining:5 *123 (490 per attempt) detailed view END Submit Hint I give up! Hints: 200 deduction per hint. Hints remaining: 1 Feedback: 2% deduction per feedback. 50% Part (b) Find the height above the floor, in meters, of the top edge of the shortest mirror in which he can see both the top of his head and his feet. This height is denoted ht in the figureExplanation / Answer
a) a = 0.15 / 2 = 0.075 m
b = 1.5 / 2 = 0.75 m
total height = 1.5 + 0.15 = 1.65 m
height of the bottom edge of shortest mirror = 0.75 m
b) L = h - (a + b) = 1.65 - (0.075 + 0.75) = 0.825 m
b + L = 0.75 + 0.825= 1.575 m
height of the top edge of shortest mirror = 1.575 m
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.