What is the average power? 9.79 EXERCISE HINTS: GETTING STARTED I rM STUCK! A 9.

Question

What is the average power? 9.79 EXERCISE HINTS: GETTING STARTED I rM STUCK! A 9.00-V battery delivers a current of 1.23 A to the lightbulb filament of a pocket flashlight. (a) How much charge passes through the filament in 1.60 min? (b) How many electrons pass through the filament? electrons (c) Calculate the energy delivered to the filament during that time. (d) Calculate the power delivered by the battery. Need Help?Read R 2. -16 points SerCP11 17.AE.003 EXAMPLE 17.3The Resistance of Nichrome Wire GOAL Combine the concept of resistivity with Ohm's law

Explanation / Answer

here,

voltage of battery , V = 9 V

current , I = 1.23 A

a)

time interval , t = 1.6 min = 1.6 * 60 s

the charge passed through the filament , Q = I * t

Q = 1.23 * 1.6 * 60 C

Q = 118.1 C

b)

the number of electrons passed , N = Q/e

N = 118.1 /( 1.6 * 10^-19) electrons

N = 7.38 * 10^20 electrons

c)

the energy delivered , E = V * I * t

E = 9 * 1.23 * 1.6 * 60 J

E = 1062.72 J

d)

the power delivered by battery , P = V * I

P = 9 * 1.23 W

P = 11.07 W

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