The temperatures of three Pyrex glass blocks are raised by the same amount. The

Question

The temperatures of three Pyrex glass blocks are raised by the same amount. The sizes (length x width x height) of the blocks are
block 1: 2D x 2D x D
block 2: D x D x 2D
block 3: 2D x D x 2D
with D = 5 cm.

e) For each of the blocks, calculate the change in height when the temperature is raised by 100oC.(answers are delta h1=0.0015cm,delta h2 = 0.003cm,delta h3 = 0.003cm)

The temperatures of three Pyrex glass blocks are raised by the same amount. The sizes (length x width x height) of the blocks are
block 1: 2D x 2D x D
block 2: D x D x 2D
block 3: 2D x D x 2D
with D = 5 cm.

Explanation / Answer

= (1/L)(L/T) and for Pyrex is about 3 * 10-6 K-1. Solving for L,

L = L T

Block 1 is 0.05 m high, and blocks 2 and 3 are 0.10 m high. So,

(3 * 10-6 K-1)(0.05 m)(100 K) = 15 * 10-6 m = 15 * 10-4 cm = 0.0015 cm for block 1

(3 * 10-6 K-1)(0.10 m)(100 K) = 30 * 10-6 m = 30 * 10-4 cm = 0.003 cm for blocks 2 and 3

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