The drawing below shows a copper wire (negligible resistance) bent into a circul

Q: The drawing below shows a copper wire (negligible resistance) bent into a circul

(V = -dPhi/dt = - rac{d}{dt} BA = -B rac{d}{dt} A = B rac{d}{dt}( heta/2 r^2)) (= B2 hetadot heta r^2/2 = B heta omega r^2) (I = V/R) (I = B heta omega r^2/R)

ID: 1896955 • Letter: T

Question

The drawing below shows a copper wire (negligible resistance) bent into a circular shape with a radius of 0.451 m. The radial section BC is fixed in place, while the copper bar AC sweeps around at an angular speed of 15.2 rad/s. The bar makes electrical contact with the wire at all times. The wire and the bar have negligible resistance. Assume R = 2.81 ?. A uniform magnetic field exists everywhere, is perpendicular to the plane of the circle, and has a magnitude of 3.52E-3 T. Calculate the magnitude of the current induced in the loop ABC.

Explanation / Answer

(V = -dPhi/dt = -rac{d}{dt} BA = -Brac{d}{dt} A = B rac{d}{dt}( heta/2 r^2)) (= B2 hetadot heta r^2/2 = B heta omega r^2) (I = V/R) (I = B heta omega r^2/R)

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The drawing below shows a copper wire (negligible resistance) bent into a circul

The drawing below shows a graph of a set of equipotential surfaces in cross sect

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The drawing below shows a copper wire (negligible resistance) bent into a circul

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