A 3.1 Ohm resistor, a 9.8 Ohm resistor and a 9 Ohm resistor are connected in ser

Question

A 3.1 Ohm resistor, a 9.8 Ohm resistor and a 9 Ohm resistor are connected in series with a 36 V battery. Calculate the equivalent resistance. Answer in units of Ohm 020 (part 2 of 5) What is the current in each resistor? Answer in units of A 021 (part 3 of 5) the resistors are instead connected in parallel across the battery, what is the equivalent resistance? Answer in units of Ohm 022 (part 4 of 5) What is the current in the 3.1 Ohm resistor? Answer in units of A 023 (part 5 of 5) What is the current in the 9 Ohm resistor? Answer in units of A

Explanation / Answer

a).Req=3.1+9.8+9=21.9 ohms

b).i=V/R=36/21.9=1.644 A in each resistor

c).if resistors connected in parallel then

Req=(3.1-1+9.8-1+9-1)-1=1.87 ohms

d).when connected in parallel

total current=36/1.87=19.25 A

current in 3.1 ohm=(1.87/3.1)*19.25=11.61 A

e).current in 9 ohm=(1.87/9)*19.25=3.99 A

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