A conducting wire is parallel to the y axis. It moves in the positive x directio

Question

A conducting wire is parallel to the y axis. It moves in the positive x direction with a speed of 22 m/s in a magnetic field of (0.2 T) . The charge on an electron is -1.6 Times 10-19 C. What is the magnitude of the magnetic force oil an electron in the conductor? Answer in units of N Because of this magnetic force, electrons move to one end of the wire leaving the other end positively charged, until the electric field due to this charge separation exerts a force on the electrons that balances the magnetic force. Find the magnitude of this electric field in the steady state. Answer in units of V/m Suppose the moving wire is 2.04 m long. What is the potential difference between its two ends due to this electric field? Answer in units of V

Explanation / Answer

1. magnetic force F = q(v x B)
F = -1.6*10^-19 ( 22 i X 0.2K)

= + 7.04*10^-19j N

2. F = Eq

E = 7.04*10^-19/1.6*10^-19

E = 4.4 V/m

3. E = V/d

V = 4.4*2.04

= 8.97 volts

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