In the following exoergic nuclear reaction, 12D + 13T ? 01n + 24He a.) What perc
ID: 1898740 • Letter: I
Question
In the following exoergic nuclear reaction, 12D + 13T ? 01n + 24He
a.) What percentage of the initial mass is converted into energy? The atomic masses are given in the above table in unified atomic mass units. [Do not enter units.]
b.)How much energy is released in the above reaction?
Explanation / Answer
recation is not balanced we observe atomic number of 15 on LHS and 48 on RHS balanced reaction can be 24D +26T -->-26 n + 25 He a) mass lost in reactions =mass of reactants - mass of products = 24(2.014102) +26(3.016049) -26(1.008665)- 25(4.002603) =0.49 percentage of mass converted to energy = 0.49/(mass of reactants) x100 =0.49/(126.7557) x100 = 0.386 % b) energy = mass defect x931.5 MeV = 0.49 x931.5 = 456.435 MeV
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