In outer space, far from other objects, block 1 of mass 40kg is at position r_1

Question

In outer space, far from other objects, block 1 of mass 40kg is at position
r_1 = <8,9,0>m,
and block 2 of mass 1000kg is at position
r_2 = <17,13,0>m
Since the z components of position are zero, the (vector) gravitational force acting on block 2 due to block 1 will be of the form:
F_gr = <F_grx, F_gry, 0>N.

At 4.6s after noon both blocks were at rest at positions given above. At 4.7s after noon, what is the (vector) momentum of block 2?
Find p_fx, p_fy. Answer p_fx in units of N. Answer p_fy in units of kg*m/s.

Explanation / Answer

r = ((17-8)*(17-8)+(13-9)*(13-9)) = 97 = 9.8489 m

F = Gm1 m2/r^2 = 6.673e-11*40*1000/97 = 2.7518e-8 N

a1 = F/m1 = 2.7518e-8/40 = 0.41237 m/s2

a2 = F/m2 = 2.7518e-8/1000 = 2.7518e-11 m/s2

= Arctan((13-9)/(17-8)) = 23.9625

v = a2 t = 2.7518e-11 * 0.1 = 2.7518e-12 m/s

p = m v = 1000 * 2.7518e-12 = 2.7518e-9

p_x = -2.7518e-9 cos = -2.51e-9 kg*m/s

p_y = -2.7518e-9 sin = -1.12e-9 kg*m/s

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