A gymnast of mass 68.0{\ m kg} hangs from a vertical rope attached to the ceilin

Question

A gymnast of mass 68.0{ m kg} hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume that the rope does not stretch. Use the value 9.81 { m m/s^2} for the acceleration of gravity.Calculate the tension T in the rope if the gymnast hangs motionless on the rope.Calculate the tension T in the rope if the gymnast climbs the rope at a constant rate.Calculate the tension T in the rope if the gymnast climbs up the rope with an upward acceleration of magnitude 0.600{ m m/s^2} .Calculate the tension T in the rope if the gymnast slides down the rope with a downward acceleration of magnitude 0.600{ m m/s^2} .

Explanation / Answer

A. T = mg = 60 * 9.81 = 588.6 N B. T = mg = 60 * 9.81 = 588.6 N C. T = mg + F = 60 * 9.81 + 60 * 1.5 = 678.6 N D. T + F = mg T = mg - F = 60 * 9.81 - 60 * 1.5 = 498.6 N

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