A battery is connected in series with a 0.31-? resistor and an inductor, as show

Question

A battery is connected in series with a 0.31-? resistor and an inductor, as shown in the figure below. The switch is closed at t = 0. The time constant of the circuit is 0.10 s, and the maximum current in the circuit is 8.2 A.

(a) Find the emf of the battery.
V

(b) Find the inductance of the circuit.
mH

(c) Find the current in the circuit after one time constant has elapsed.
A

(d) Find the voltage across the resistor after one time constant has elapsed.
V

(e) Find the voltage across the inductor after one time constant has elapsed.
V

Explanation / Answer

(a)

EMF = I*R = 8.2*0.31 = 2.542 V

(b)

L = 0.1*0.31 = 31 mH

(c)

I(0.1) = 8.2*(1-e^-1)

= 5.1834 A

(d)

V(resistance) = 1.61 V

(e)

V(inductor) = 2.542-1.61 = 0.93515 V

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.