A bronze statue covered with gold has a mass of 9.00 kg. When submerged in water

Question

A bronze statue covered with gold has a mass of 9.00 kg. When submerged in water, the statue has an apparent mass of 7.90 kg. If the density of bronze is 8.00 g/cc and the density of gold is 19.3 g/cc, find the mass of the bronze and the mass of the gold contained in the statue.

Explanation / Answer

Let mass of bronze = x Kg =>Mass of gold = 9-x Kg When submerged in water, apparent mass = 7.9 Kg =>(9*9.81)-((x/8000)*1000*9.81)-(((9-x)/19300)*1000*9.81) = (7.9*9.81) =>10.791 = ((x/8000)*1000*9.81) + (((9-x)/19300)*1000*9.81) =>(x/8000) + ((9-x)/19300) = 0.0011 =>19300x + 72000 - 8000x = 169840 =>x = mass of bronze = 8.65840708 Kg =>9-x = Mass of gold = 0.34159292 Kg

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.