Calculate the period prevalence from October 1, 2004, to September 30, 2005. The

Question

Calculate the period prevalence from October 1, 2004, to September 30, 2005. The numerator of period prevalence includes anyone who was ill any time during the period. In Figure 3.1, the first 10 persons were all ill at some time during the period.

Show the formula, calculations and the interpret the results

PROBLEM 1. (6 points) Figure 1, below represents 10 new cases of illness in a population of 20 persons over a period of 15 months. Each horizontal line represents the period of time one person spends beingi. The down arrow indicates the date of onset of illness. The solid line represents the duration of illness. The up arrow and the cross represent the date of recovery and date of death, respectively FIGURE 1. New Cases of lllness from October 1, 2004-September 30, 2005 Date of onset of illness Date of death Date of recovery Person # 1 2 3 4 5 7 8 10 Oct. 1, 2004 Apr. 1, 2005 Sept. 30, 2005

Explanation / Answer

Answer:

Period prevalence refers to prevalence measured over an interval of time. It is the proportion of persons with a particular disease or attribute at any time during the interval.

Calculating prevalence of disease =

(All new and pre-existing cases during a given time period / Population during the same time period) x 10n

The value of 10n is usually 1 or 100 for common attributes.

Numerator = 10 (number of ALL ill individuals no matter when s/s started)

Denominator = 20 (total population living or dead during the same time period)

Period prevalence = (10/20) x 100 = 50% (Total of 50% of this population was ill during this period)

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