A 142Kg create is placed on an inclined ramp. when the angle the ramp makes the

Question

A 142Kg create is placed on an inclined ramp. when the angle the ramp makes the horizontal is increased to (alfa), the crate beging to slide downward.

A) Draw a free-body diagram showing the forces acting on the crate.

B) Calculate equations representing the components the forces actiong on the crate.

C)if the coefficient of static friction between the crate and the ramp is 0.65, what is the angle (alfa) when the crate just begings to slide downward?

Explanation / Answer

for every such sliding it is necessary that, the tangent of the inclination=coeffct. of friction so if at 22 degree the body starts to slide means, coeffct. of friction= tan 22 =0.4040 and the sliding depends only on coeffct of friction ie inclination so every mass slides at 22 degrees a) mg sin 22º = µ * N ----> N = mg cos 22º --> µ = mg sin 22/ mg cos 22 µ = tan 22 = 0.404 b) µ = tan 22 = 0.404 ( µ does not depend on the mass

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