Calculate the torque (magnitude and direction) about point due to the force in e

Question

Calculate the torque (magnitude and direction) about point due to the force in each of the situations sketched in the figure below --copy and paste the LINK BELOW to see the image(the angles are: A. 90, B. 120, C. 30, D. 60, E. 60, F. 0) In case a, the force and the rod both lie in the plane of the page, the rod has length 6.00 , and the force has magnitude 12.0. In case b, the force and the rod both lie in the plane of the page, the rod has length 6.00 , and the force has magnitude 12.0. In case c, the force and the rod both lie in the plane of the page, the rod has length 6.00 , and the force has magnitude 12.0. In case d, the force and the rod both lie in the plane of the page, the rod has length 6.00 , and the force has magnitude 12.0. In case e, the force and the rod both lie in the plane of the page, the rod has length 6.00 , and the force has magnitude 12.0. In case f, the force and the rod both lie in the plane of the page, the rod has length 6.00 , and the force has magnitude 12.0. http://session.masteringphysics.com/problemAsset/1263378/3/1026422.jpg (the answer to A was 72.)

Explanation / Answer

a) T = r x f Where r is the distance away from the pivot point and f is the force perpendicular to the arm of rotation. T = r x Fg T = r x mg T = (0.12 m)(0.010 kg)(9.81 m/s^2) T = 0.0118 Nm You determine direction with the right hand rule. Curl your fingers (of you right hand!) in the direction of the rotation and your thumb will point towards the direction of the torque. So in this case the torque will be into the page. b) Exact same thing except the torque is coming out of the page. c) Zero torque because the forces are clearly equal and opposite. d) T1 = r x (m1)g T1 = (0.12 m)(0.010 kg)(9.81 m/s^2) T1 = 0.0118 Nm [into the page] T2 = r x (m2)g T2 = (0.7 m)(0.010 kg)(9.81 m/s^2) T2 = 0.0687 Nm [out of the page] Let's just define out of the page as positive. T net = T1 + T2 T net = - 0.0118 Nm + 0.0687 Nm T net = 0.0569 Nm [out of the page]

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