Calculate the temperature data below for coefficient ofvariation and the coeffic

Question

Calculate the temperature data below for coefficient ofvariation and the coefficient of skewness for the data shown.(please show work) 77, 53, 50, 72, 68, 79, 73, 74, 54, 54, 52, 63, 52, 64, 79,73, 75 I need the mean, deviation, absolute, squared, of thesenumbers I don't understand how to get the deviation, absolute orsquared. I would really appreciate help for this, I have been soooooooostressed not being able to figure this out. Thankyou!!!!!!!!!! Calculate the temperature data below for coefficient ofvariation and the coefficient of skewness for the data shown.(please show work) 77, 53, 50, 72, 68, 79, 73, 74, 54, 54, 52, 63, 52, 64, 79,73, 75 I need the mean, deviation, absolute, squared, of thesenumbers I don't understand how to get the deviation, absolute orsquared. I would really appreciate help for this, I have been soooooooostressed not being able to figure this out. Thankyou!!!!!!!!!!

Explanation / Answer

. 1.   I feel it necessary to relay Gort'sview of statistics. Humans are not able to absord largequantities of data; therefore they have devised methods ofdistilling the information about a large population into a few"characteristic" figures. The mean is certaintely the mostcommon and pops up everywhere: GPAs for example. Thenext most common is the standard deviation which is anumber that reflects how much the population varied about itsmean or average. For example, if the mean value of a runningthe 100 yard dash is 15 seconds and the standard deviation is 1second, that means the vast majority of the population run the 100yard dash near 15 seconds. If, on the other hand, thestandard deviation is 5 seconds that means the population has amuch larger spread, i.e., a few can run really fast... say 9seconds, but in the same population, however, a few run it reallyslow... say 21 seconds. Skewness is a number that tells youwhether the deviation is more to the lower side of the averageor more to the upper side of the average. Thus, by digestingonly 3 numbers, I might know quite a bit about a very largepopulation of samples... even sample spaces that might containmillions of sample points like a manufacturing plant. So backto solutions... 2.   The mean is the average of thedistribution. Calculate the total of the values within thesample space and then divide by the total number of samplepoints. 3.   The total of the values within the samplespace is: 1058 4.   The total number of sample pointsis: 16 5.    = mean = 1058/16 =66.125 6.   2 = variance =(1/16)*(x - )2 = E[x2] =(1/16)*[each of the sample points]2 -2       where: = mean 7.   2 =(1/16)*[(77)2 +(53)2 +(50)2+(72)2 +(68)2 +(79)2+(73)2 +(74)2 +(54)2+(52)2 +(63)2 +(52)2+(64)2 +(79)2 +(73)2+(75)2] - (66.125)2 8.   I did not actually run the above equationthrough my calculator as Excel has statistical functions; so I justplace the numbers into the sheet and let it do thework. 9.   2 =107.2344 10.    = standard deviation =(2) = (107.2344)   =10.3554 11.   skewness = -0.3931 . .

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